4 Bytes To Bits On little endian machines the first byte holds the least signficant bits That means that on little endian machines this code takes the most significant 8 bits and stores them in the place where the least significant bits go changing the value 2130706432 is 0x7F000000 in hex and 127 is 0x0000007F Also x int a results in undefined
If a character is 8 bits or 1 byte then a WORD must be at least 2 characters so 16 bits or 2 bytes Traditionally you might think of a word as a varying number of characters but in a computer everything that is calculable is based on static rules What I want to do it to read up to 4 bytes and create a int value from those but I don t know how to do it I kind of feel like I have to grab 4 bytes at a time and perform one byte operation like FF and stuff like that to create the new int What s the idiom for this EDIT
4 Bytes To Bits
4 Bytes To Bits
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If you have a whole array of bytes that need to be re interpreted as floats you can call the following procedure for each consecutive sequence of 4 bytes in the array if necessary to switch the byte order e g if you are running on a little 4 x 1024 bytes 2 2 x 2 10 bytes 4 KB i e 2 12 bytes The size of each page is thus 4 KB Kilo bytes NOT kilo bits As Depaak said we calculate the number of pages in the page table with this formula
The memory bus is at least 64 bits wide and transfers in bursts of 64 bytes a cache line and execution unit to cache paths are at least 128 bits wide or 256 or even 512 bits wide Whatever the native machine word size of modern x86 is it s not 16 bits but modern x86 still uses 8086 terminology If the variable is int the ALU always does operations on 32 bits and leaves the other 32 bits of the ALU capability unused Operations on a byte most likely leave 58 bits of the ALU unused These operations always take place in one clock cycle so
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NB The 4 is because there are 8 bits in 1 byte which is an unsigned char so we want to take the other half and so on We could easily apply this solution to 4 bytes with only two additional lines and following the same logic Since both mask complement each other we can even use in order to switch bits and saving some ink In C an int and float each take up 4 bytes or 32 bits in memory The difference between int and float is not the number of bits they take up in memory but rather in the way the ALU Arithmetic Logic Unit treats each number An int is treated as the integer represented by its bits using two s complement notation
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On little endian machines the first byte holds the least signficant bits That means that on little endian machines this code takes the most significant 8 bits and stores them in the place where the least significant bits go changing the value 2130706432 is 0x7F000000 in hex and 127 is 0x0000007F Also x int a results in undefined
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If a character is 8 bits or 1 byte then a WORD must be at least 2 characters so 16 bits or 2 bytes Traditionally you might think of a word as a varying number of characters but in a computer everything that is calculable is based on static rules
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4 Bytes To Bits - If you have a whole array of bytes that need to be re interpreted as floats you can call the following procedure for each consecutive sequence of 4 bytes in the array if necessary to switch the byte order e g if you are running on a little
