R 3 1 2 4 2 3 Answer Let R be the relation 1 2 1 3 2 3 2 4 3 1 and let S be the relation 2 1 3 1 3 2 4 2 To compose S R we compare pairs in R with pairs in S and create new pairs
begingroup 2 3 in R 1 and 3 2 in R 1 which speaks in favour of symmetry but is not enough to prove it you have 2 4 in R 1 and 4 2 notin R 1 Free math problem solver answers your algebra geometry trigonometry calculus and statistics homework questions with step by step explanations just like a math tutor
R 3 1 2 4 2 3 Answer
R 3 1 2 4 2 3 Answer
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Complete step by step answer It is given that R 1 3 4 2 2 4 2 3 3 1 on A 1 2 3 4 For R to be reflexive a a should exist in R where a is an element of the set A But Let A 1 2 3 4 Let R the relation on the set A or R 1 1 1 2 1 3 2 1 3 2 3 3 4 4 Find R o R as a set of tuples I am not certain how to approach this problem
Ex 1 1 15 Let R be the relation in the set 1 2 3 4 given by R 1 2 2 2 1 1 4 4 1 3 3 3 3 2 Choose the correct answer A R is reflexive and symmetric but not transitive B R is reflexive and transitive Write the smallest reflexive relation on set A 1 2 3 4 Let R a a 3 a is a prime number less than 5 be a relation Find the range of R R is a relation on the set Z of integers and it is
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Given R 1 3 4 2 2 4 2 3 3 1 be a relation on the set A 1 2 3 4 a Since 2 4 R and 2 3 R So R is not a function The total number of functions f 1 2 3 4 1 2 3 4 5 6 such that f 1 f 2 f 3 is equal to Q5 Let x x5 2ex 4 for all x R Consider a function g x such that gof x x for all
QuickMath will automatically answer the most common problems in algebra equations and calculus faced by high school and college students The algebra section allows you to expand Complete step by step answer A relation between two sets is a collection of ordered pairs containing one object from each set If the object x is from the first set and the
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Let R be the relation 1 2 1 3 2 3 2 4 3 1 and let S be the relation 2 1 3 1 3 2 4 2 To compose S R we compare pairs in R with pairs in S and create new pairs
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begingroup 2 3 in R 1 and 3 2 in R 1 which speaks in favour of symmetry but is not enough to prove it you have 2 4 in R 1 and 4 2 notin R 1

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R 3 1 2 4 2 3 Answer - Free math problem solver answers your algebra homework questions with step by step explanations